Escape velocity is the minimum speed an object must achieve to escape the gravitational field of a massive body without any further propulsion, assuming no atmospheric drag and a radial (straight-up) trajectory. It is derived by equating the kinetic energy of the object to the magnitude of its gravitational potential energy. Escape velocity is a critical concept in rocketry and planetary science: Earth's escape velocity is approximately 11.2 km/s, while the Sun's is about 617.5 km/s, and a black hole's escape velocity at the event horizon equals the speed of light.
v_e = sqrt(2 × G × M / r)
LaTeX: v_e = \sqrt{\frac{2GM}{r}}
| Symbol | Meaning | Unit |
|---|---|---|
| v_e | Escape velocity | m/s |
| G | Universal gravitational constant (6.674 × 10⁻¹¹) | N·m²/kg² |
| M | Mass of the central body | kg |
| r | Distance from the centre of the body | meters (m) |
Problem
Calculate the escape velocity from the surface of Mars. (Mass of Mars M = 6.417 × 10²³ kg, Radius of Mars R = 3.390 × 10⁶ m, G = 6.674 × 10⁻¹¹ N·m²/kg²)
Solution
Step 1: Write the formula: v_e = sqrt(2 × G × M / r). Step 2: Calculate numerator: 2 × G × M = 2 × 6.674 × 10⁻¹¹ × 6.417 × 10²³ = 8.566 × 10¹³. Step 3: Divide by r: 8.566 × 10¹³ / 3.390 × 10⁶ = 2.527 × 10⁷ m²/s². Step 4: Take square root: v_e = sqrt(2.527 × 10⁷) = 5027 m/s.
Answer
Escape velocity from Mars ≈ 5,027 m/s ≈ 5.03 km/s
| Body | Mass (kg) | Radius (km) | Escape Velocity (km/s) |
|---|---|---|---|
| Moon | 7.34 × 10²² | 1,737 | 2.38 |
| Mars | 6.42 × 10²³ | 3,390 | 5.03 |
| Earth | 5.97 × 10²⁴ | 6,371 | 11.2 |
| Saturn | 5.68 × 10²⁶ | 58,232 | 35.5 |
| Jupiter | 1.90 × 10²⁷ | 69,911 | 59.5 |
| Sun | 1.99 × 10³⁰ | 696,000 | 617.5 |
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