A hydraulic jump is a phenomenon in open-channel flow where rapidly flowing supercritical water (Froude number > 1) abruptly transitions to slower subcritical flow (Froude number < 1), accompanied by a significant rise in water depth and intense turbulence. The jump dissipates a large amount of kinetic energy as heat and sound, making it useful as an energy dissipator downstream of spillways, weirs, and sluice gates to protect channel beds from erosion. The sequent (conjugate) depths before and after the jump are related by the Belanger equation.
y2/y1 = (1/2) × (-1 + sqrt(1 + 8·Fr1²))
LaTeX: \frac{y_2}{y_1} = \frac{1}{2}\left(-1 + \sqrt{1 + 8\,Fr_1^2}\right)
| Symbol | Meaning | Unit |
|---|---|---|
| y_1 | Upstream (supercritical) flow depth | m |
| y_2 | Downstream (subcritical) sequent depth | m |
| Fr_1 | Upstream Froude number = V₁ / √(g·y₁) | dimensionless |
| V_1 | Upstream mean flow velocity | m/s |
| g | Acceleration due to gravity | m/s² |
Problem
Water flows at depth y₁ = 0.30 m with velocity V₁ = 4.5 m/s in a wide rectangular channel (g = 9.81 m/s²). Confirm the flow is supercritical and find the sequent depth y₂.
Solution
Froude number: Fr₁ = V₁ / √(g·y₁) = 4.5 / √(9.81 × 0.30) = 4.5 / √2.943 = 4.5 / 1.715 = 2.62 > 1 → supercritical (hydraulic jump will form). Sequent depth ratio: y₂/y₁ = (1/2) × (−1 + √(1 + 8 × 2.62²)) = 0.5 × (−1 + √(1 + 8 × 6.864)) = 0.5 × (−1 + √(56.91)) = 0.5 × (−1 + 7.544) = 0.5 × 6.544 = 3.272. Sequent depth: y₂ = 3.272 × 0.30 = 0.982 m.
Answer
y₂ ≈ 0.98 m; Fr₁ = 2.62 (supercritical upstream)
| Jump Type | Fr₁ Range | Description | Energy Loss |
|---|---|---|---|
| Undular jump | 1.0 – 1.7 | Slight undulations, no roller | Very small (< 5%) |
| Weak jump | 1.7 – 2.5 | Small rollers, smooth surface | Small (5–15%) |
| Oscillating jump | 2.5 – 4.5 | Irregular, jet oscillates | Moderate (15–45%) |
| Steady jump | 4.5 – 9.0 | Well-defined, stable | High (45–70%) |
| Strong jump | > 9.0 | Very turbulent, rough surface | Very high (> 70%) |
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