Membrane potential is the electric potential difference across a cell's plasma membrane, arising from the unequal distribution of ions (Na⁺, K⁺, Cl⁻, Ca²⁺) between the intracellular and extracellular environments. In neurons and muscle cells, the resting membrane potential is approximately −70 mV (inside negative), maintained by the Na⁺/K⁺-ATPase pump and selective ion channels. Changes in membrane potential — action potentials — underlie nerve impulse transmission and muscle contraction.
E_m = (RT / zF) × ln([X]_outside / [X]_inside)
LaTeX: E_m = \frac{RT}{zF} \ln\frac{[X]_o}{[X]_i}
| Symbol | Meaning | Unit |
|---|---|---|
| E_m | Equilibrium (Nernst) potential for ion X | mV |
| R | Universal gas constant | J mol⁻¹ K⁻¹ |
| T | Absolute temperature | K |
| z | Valence (charge) of the ion | dimensionless |
| F | Faraday's constant (96485) | C mol⁻¹ |
| [X]_o | Extracellular ion concentration | mM |
| [X]_i | Intracellular ion concentration | mM |
Problem
Calculate the equilibrium potential for K⁺ at 37 °C. Given: [K⁺]_outside = 5 mM, [K⁺]_inside = 140 mM, z = +1.
Solution
Step 1: Convert temperature: T = 37 + 273.15 = 310.15 K. Step 2: Compute RT/zF: (8.314 × 310.15) / (1 × 96485) = 2578.0 / 96485 ≈ 0.02671 V. Step 3: Compute ln([K⁺]_o / [K⁺]_i) = ln(5 / 140) = ln(0.03571) ≈ −3.332. Step 4: E_K = 0.02671 × (−3.332) ≈ −0.08899 V = −89 mV.
Answer
E_K ≈ −89 mV
| Ion | Intracellular (mM) | Extracellular (mM) | Equilibrium Potential (mV) |
|---|---|---|---|
| K⁺ | 140 | 5 | −89 |
| Na⁺ | 12 | 145 | +67 |
| Cl⁻ | 4 | 120 | −86 |
| Ca²⁺ | 0.0001 | 1.5 | +122 |
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From Latin "membrana" (thin skin) + Latin "potentia" (power, ability). The concept was quantified by Walther Nernst in the 1880s and expanded by Goldman, Hodgkin, and Katz with the GHK equation in 1943.