A thermodynamic cycle is a series of thermodynamic processes that return a system to its initial state, enabling continuous conversion of heat into work or vice versa. Engineering thermodynamic cycles such as the Rankine, Brayton, and Otto cycles form the basis of power plants, jet engines, and internal combustion engines respectively. The thermal efficiency of a cycle quantifies the fraction of heat input that is converted into net work output.
η_th = 1 - Q_out/Q_in = W_net/Q_in
LaTeX: \eta_{th} = 1 - \frac{Q_{out}}{Q_{in}} = \frac{W_{net}}{Q_{in}}
| Symbol | Meaning | Unit |
|---|---|---|
| \eta_{th} | Thermal efficiency | dimensionless |
| Q_{in} | Heat input to the cycle | J |
| Q_{out} | Heat rejected from the cycle | J |
| W_{net} | Net work output | J |
Problem
A steam power plant operating on the Rankine cycle receives 3000 kJ/kg of heat and rejects 1900 kJ/kg. Calculate the thermal efficiency and net work output per kg of steam.
Solution
Step 1: Identify given values — Q_in = 3000 kJ/kg, Q_out = 1900 kJ/kg. Step 2: Net work: W_net = Q_in − Q_out = 3000 − 1900 = 1100 kJ/kg. Step 3: Thermal efficiency: η = W_net / Q_in = 1100 / 3000 = 0.3667.
Answer
η_th = 36.7%, W_net = 1100 kJ/kg
| Cycle | Application | Working Fluid | Typical Efficiency |
|---|---|---|---|
| Rankine | Steam power plants | Water/steam | 30–45% |
| Brayton | Gas turbines, jet engines | Air/combustion gas | 25–40% |
| Otto | Petrol engines | Air-fuel mixture | 25–35% |
| Diesel | Diesel engines | Air-fuel mixture | 35–45% |
| Refrigeration (vapour) | Refrigerators, AC | Refrigerant | COP 2–5 |
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From Greek "thermē" (heat) and "dynamikos" (powerful, active). The term "thermodynamic" was introduced by Lord Kelvin (William Thomson) around 1849. "Cycle" comes from Greek "kyklos" (circle), denoting the return to initial state.