Power factor is the ratio of real power (watts) to apparent power (volt-amperes) in an AC circuit, representing how effectively electrical power is being converted into useful work. It equals the cosine of the phase angle between the voltage and current waveforms, ranging from 0 (purely reactive) to 1 (purely resistive). A low power factor indicates high reactive power circulation, which increases current for a given load, causing extra losses in transmission lines, and utilities typically penalise industrial consumers for poor power factor below 0.85.
PF = cos(φ) = P/S = P / √(P² + Q²)
LaTeX: PF = \cos\phi = \frac{P}{S} = \frac{P}{\sqrt{P^2 + Q^2}}
| Symbol | Meaning | Unit |
|---|---|---|
| PF | Power factor | Dimensionless (0 to 1) |
| φ | Phase angle between voltage and current | degrees or radians |
| P | Real (active) power | W (watts) |
| S | Apparent power | VA (volt-amperes) |
| Q | Reactive power | VAR (volt-ampere reactive) |
Problem
An industrial motor draws 10 kW of real power and 7.5 kVAR of reactive power from a 230 V, 50 Hz supply. Calculate the apparent power S, power factor PF, and the required capacitor size to correct the power factor to 0.95 lagging.
Solution
Step 1: Calculate apparent power. S = √(P² + Q²) = √(10000² + 7500²) = √(10⁸ + 5.625×10⁷) = √(1.5625×10⁸) = 12,500 VA = 12.5 kVA Step 2: Calculate current power factor. PF = P/S = 10,000 / 12,500 = 0.8 lagging φ₁ = arccos(0.8) = 36.87° Step 3: Find target reactive power for PF = 0.95. φ₂ = arccos(0.95) = 18.19° Q₂ = P × tan(φ₂) = 10,000 × tan(18.19°) = 10,000 × 0.3287 = 3,287 VAR Step 4: Required capacitor reactive power. Q_C = Q₁ − Q₂ = 7,500 − 3,287 = 4,213 VAR Step 5: Capacitor size at 230 V, 50 Hz. C = Q_C / (ω × V²) = 4213 / (2π×50 × 230²) = 4213 / 16,597,300 ≈ 253.8 µF
Answer
S = 12.5 kVA, PF = 0.8 lagging; correction capacitor required: C ≈ 254 µF
| Quantity | Symbol | Unit | Description |
|---|---|---|---|
| Real power | P | W (watt) | Actual work done — heat, light, motion |
| Reactive power | Q | VAR | Energy stored/released by inductors and capacitors |
| Apparent power | S | VA | Vector sum: S = √(P²+Q²) |
| Power factor | PF | Dimensionless | cos(φ) = P/S, ranges 0–1 |
| Phase angle | φ | degrees | Angle between V and I phasors |
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